A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes up to 2 in height further, find the magnitude of the force. Consider g = 10m/s 2

A. 22N B. 16N C. 20N D. 4N Mass ,m=0.2kg Total height, h=0.2+2=2.2m Work done =Difference in potential energy. F.S=mgh where S is the distance for e hich the force is applied by hand, S=0.2m F= S mgh ​ = 0.2 0.2×10×2.2 ​ F=22N

A body is falling freely under gravity. How much distance it falls during an interval of time between 1st and 2nd seconds of its motion, taking g=10 ?

A. 15 m B. 20 m C. 5 m D. 25 m answer is 15 m S=ut+1/2gt^2 u=0 ,g = 10ms-2 During ist time interval S1=0+1/2(10)(1)^2 S1=5m During 2nd time interval S2=0+1/2(10)(2)^2 S2=20m Distance covered by body during an interval of time between first and second seconds of its motion = (S2 – S1 ) … Read more